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apldeap123
offline
apldeap123
1,708 posts
Farmer

Objective:

- Players must reach exactly 12 to win.

How to Play:

- A six-sided die is used.
- The player must roll the die. If an even number is used (e.g, 2, 4, 6),
you add that number to the previous rolled number.
- If an odd number is rolled (1, 3, 5) you subtract that amount from the
previous number.
- A new count always begins with the number 1.
- The player who restarts the count must roll the dice and add/subtract the
resulting number from 1.
- The count must be restarted if:
- The count reaches zero or goes into negative numbers.
- A player rolls the same number as the previous poster.

Example:
P1: 1 (dice rolled 4) 1+4=5
P2: 5 (dice rolled 2) 5+2=7
P1: 7 (dice rolled 3) 7-3=4
P3: 4 (dice rolled 3) restart

Things to Remember:

- You can back-to-back post! Just don't post three times in a row.

Once a successful count has been reached, please notify me in my profile comments.

EDIT: Rules changed for clarification.

  • 80 Replies
dorukayhan
offline
dorukayhan
1,318 posts
Bard

ne:

let's try it now ThisOneShouldBe6 = 6

doqck.doesNotCareTheFactThatThisIsPseudocode(true);
RNG.useThisAlgorithmToMakeRandomNumbers("x = (x mod 6) + 1");
DICE RESULTS
6 = ThisOneShouldBe6
HahiHa
offline
HahiHa
8,259 posts
Regent

7. Aw, we were so close. 1d6=6

DICE RESULTS
6 = 1d6
akshobhya
offline
akshobhya
5,063 posts
Justiciar

13. let me see...
1d6=6

DICE RESULTS
6 = 1d6
HahiHa
offline
HahiHa
8,259 posts
Regent

1. Three sixes in a row! Too bad it resets after 2 same numbers 1d6=3

DICE RESULTS
3 = 1d6
armorplayergc
offline
armorplayergc
16,463 posts
King

ne: (1) let's persuade dice! Six = 1

DICE RESULTS
1 = Six
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