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the_zombie_killer
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the_zombie_killer
306 posts
Nomad

Okok you have propably read the other thread 1+1=0
But now I have a NEW clean math problem for u to solve

Using four 0's get an answer of 119
You are only allowed to use +,-,*,/ and !
this is no trick it is a pure math equation

  • 125 Replies
BigP08
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BigP08
1,455 posts
Shepherd

Nan bigpo8 you FAIL try again

Was my math wrong or did I break a rule?
the_zombie_killer
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the_zombie_killer
306 posts
Nomad

Oh pple I did tell you that BRACKETS are considered multiplication rite??

johnny294
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johnny294
284 posts
Nomad

ummmmm i got it

10,000-9,881

like the_manta said you didnt say we could use other numbers

the_zombie_killer
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the_zombie_killer
306 posts
Nomad

@bigpo8 you math is wrong

TSL3_needed
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TSL3_needed
5,579 posts
Nomad

15! is 120.


Nope.

15! = 1,307,674,368,000. A very. Big. Number. 5! would be 120. Which leads me to my own dilema.

0! + 0! = 2 + 0! = 3 + 0! = 4 + 0! = 5! - 0! = 119

6, not 7.

Oh pple I did tell you that BRACKETS are considered multiplication rite??


I would think that we all would know that. I use that type of math every day :P
the_manta
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the_manta
4,535 posts
Peasant

Whoa, mega ninja'd. o_O

Anyway, bigP08, 2! =2, not 3. It's 1*2, not 1+2.

Orale', there's no notebook paper at hand...

TSL3_needed
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TSL3_needed
5,579 posts
Nomad

To speed things up, here is a list of factorials. I'm sure it's not cheating, seeing as we still have to do the rest in our heads.

the_zombie_killer
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the_zombie_killer
306 posts
Nomad

I have a feeling that DDX will get it correct...if he knows that BRACKETS are allowed
@TLS3 there is a more noobish version of this where you can use 6 zero's but u seem to have surpassed that

the_manta
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the_manta
4,535 posts
Peasant

Zombie, I've been usin g brackets.

And whatever the hell this thing's called: {

TSL3_needed
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TSL3_needed
5,579 posts
Nomad

@TLS3 there is a more noobish version of this where you can use 6 zero's but u seem to have surpassed that


Don't. Ever. Call. Me. A. Noob.

Or even relate me to one.
BigP08
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BigP08
1,455 posts
Shepherd

([(0! + 0!)!]! - 0!)! - 0! = 119

Let me see.
0! = 1.
So let's change it to this form:

([(1 + 1)!]! - 1)! - 1 = 119.
We have ([(2!)!]! - 1)! - 1 = 119.

2! = 3.

So ([3!]! - 1)! - 1 = 119.

3! = 6.

So it's (6! - 1)! - 1 = 119.
So here's my mistake. I need 6, not 6!.

So is ([(0! + 0!)!] - 0!)! - 0! = 119 Correct?
BigP08
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BigP08
1,455 posts
Shepherd

Oh sh*t, sorry everyone. I keep making the mistake of adding, not multiplying. Sorry for that. :P

the_manta
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the_manta
4,535 posts
Peasant

2! = 3.


Nope.

2!=2.
the_zombie_killer
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the_zombie_killer
306 posts
Nomad

Okok u pole seem to be having a HARD TIME lemme change the sum a bit
USE 4 ZERO'S TI GET A TOTAL OF 120 OK??
No more answers where u are trying to get 119 will be accecpted YOU MUST GET 120

BigP08
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BigP08
1,455 posts
Shepherd

[(0! + 0! + 0!)! - 0!]!
Now that I have the factorial thing right, that'd be 3!= 6.
Then 6 - 1 = 5
Then 5! = 120.
I think...

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