Okok you have propably read the other thread 1+1=0 But now I have a NEW clean math problem for u to solveUsing four 0's get an answer of 119You are only allowed to use +,-,*,/ and !this is no trick it is a pure math equation
6! = 120
Yeah, I know. I made a mistake back then, but I got it right now. Thanks, though.
ABCD = 11B = DA/C = 11|B| = -B|DDD| = DDDWhat are the terms?
No, it works. Think non-reals again.
I did, I am positive there is no way to get B = D, |B|=-B, and |DDD| = DDD
Here's a hint.If E = -i|E| = - E|EEE| = EEE.-i cubed has three neagtive ones, so the term is negative. But i squared is negative one, so that's positive, and you're left with i.
i^3=-i|iii|=iiii=-i
wait, never mind guess even my math is a little off tonight.
But we're working with -i. -i cubed is i^9, which is i, which is positive.
My calculator is horrible with i, this might take awhile.
B=-iD=-iA=-11C=-1I think
Very close.Originally, ABCD = 11.However, if we put in negative i twice, we get i^6, which is -1.So AC = -11Your other information is that A/C = 11.Just a couple missing i's here, but you got the jest of it.
so then C=1 right?
wait never mind, having issues again...
Well, I'm going to bed. It's a school night for me, so see ya later.
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