ForumsThe TavernPhysics problem

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Haku1234567890
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Haku1234567890
1,720 posts
Nomad

http://i55.tinypic.com/2hi2sdk.png

Can you tell me, what is

A1 =
A2 =
A3 =

  • 22 Replies
delossantosj
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delossantosj
6,672 posts
Nomad

hey guys i got one for ya.

help a bra out

Object A has a volume of 1.0x10^-5 and the density a density of 1300, the tension to which the string object A is attached is 0.0098 N

calculate the buoyant force on object A

calculate the density of the liquid

crazenird
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crazenird
329 posts
Nomad

bra


i think you mean bruh, as a bra is a female undergarment.

plus, in your question, you need to specify the density with units, like g/cm-3 or w/e
delossantosj
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delossantosj
6,672 posts
Nomad

volume is in meters cubed.

density is in kg/m^3

Kyouzou
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Kyouzou
5,061 posts
Jester

Both wrong, it's 'brah' learn your slang people.

crazenird
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crazenird
329 posts
Nomad

lol, im sorry kyouzou,forgive me?

delossantosj
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delossantosj
6,672 posts
Nomad

me and my friends were trying to figure this shiz out and we couldnt so save our lives.

lightcrux
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lightcrux
622 posts
Peasant

Well, for the circuit problems you can't calculate the exact values of current but can compare them,

1. A1 = highest current
2. A2 = A3 = same current reading since they are connected in parallel.

While for the buoyancy problem, considering that you dipped the object in a liquid completely by using the string,

B+T = mg => B + (9.8 x 10^-3) = (1 x 10^-5) x (1300) x 9.8
=> B = 117.6 x 10^-3

where, B = buoyancy force; m = mass of object; g =9.8 m/s^2; T = tension

As for the density,
If you remember the dude, Archimedes,

Buoyancy force = weight of fluid displaced

B = mg
Also, m = V * density

(117.6 x 10^-3) = (10^-5) x 9.8 x density
density = 1200 kg/m^3

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