If you roll a die infinite times, is there a certainty of rolling the number one?
I don't know if this is a paradox or not, but if it is I would to claim credit to [urlhttp://forums.xgenstudios.com/showthread.php?214820-Existence-Non-existence-of-Human-Life/page2]this[/url] thread.
Now, if you roll a die infinite times, you are bound to roll a one, or are you? If you roll a die infinite times, then there is the chance of rolling everything but one, as "never rolling one" is a possibility.
There is no real debate, but I just want to see where this will go for a couple pages. I would just like to her what you think.
Just trying it isn't a good enough way to determine it. You need fundamental principles to be used to prove it. Just cause you rolled a one after three rolls. Doesn't mean I can't go 99999999999999999999 rolls without a one.
Well, on a logic point of view, it's totally possible that you keep getting 6 forever and you never get a 1. But mathematically, I dunno. I'm not expert enough, but I think you should be able to prove that you'll get it sometime. But I'm definitely not sure. Good question.
Okay. The binomial distribution is a formula used to determine the likeliness of a set number of events to occur in a certain number of trials.
P(r,N)=(N!/(r!*(N-r)!))*(P^r)*(1-p)^N-r Where r is the number of events you want to occur (1) Where N is the number of trials (infinity) Where P is the probability of 1 event occurring in one trial (1/6) Plugging in those numbers and I believe using L'Hôital's rule yields the result of 0. So there is a 0 chance that you wouldn't roll a one.
Infinity is not a number. It describes a never ending number. Therfore, you can't roll 6 infite times. But I roll a one when given 10 chances.
What if you roll the number 6, an infinite amount of times, is what I meant.
Infinity can be described when you are counting forever but are only up to 7 so I think it is possible.
You don't get it. Read the OP clearly or at least take pre-Calc.
If you think it is big numbers (1000000000000000000000000000000000000) then the chances are slim.
A die can't have that many faces.
A very basic question.
Not really.
Chance of not getting 1 in a single roll is 5/6 = 0.83333 two rolls 25/36 = 0.69444 three rolls 125/216 = 0.5787
Dear God! What kind of math is this?
If I roll the die six times, the chance would always be the same. This is extremely basic math.
I am not talking about odds, I am talking about is it possible to never roll a one?
This thread is kind of pointless. There is a zero chance of that happening (meaning 1 would have to come up), I just did the limit with the Poisson distribution. I would do binomial distributional as well but that would take too long. And Milos has the right idea, but that way of doing it is a little less graceful let's say.
No idea what came out of your mouth, and I'm pretty smart.
Sorry for triple posting like this.
Why am I listening to a guy who claims he ran the numbers but can't even count to two?
I just tried it. I rolled a one on my third try.
I would like to call you a *******, but since I am trying to be nice, I will ask you to read the OP again, and read the link that I provided.
Just trying it isn't a good enough way to determine it. You need fundamental principles to be used to prove it. Just cause you rolled a one after three rolls. Doesn't mean I can't go 99999999999999999999 rolls without a one.
Well, on a logic point of view, it's totally possible that you keep getting 6 forever and you never get a 1. But mathematically, I dunno. I'm not expert enough, but I think you should be able to prove that you'll get it sometime. But I'm definitely not sure. Good question.
Yes, but at the same time, infinity is endless and is sometimes considered to be universal. When I mean universal, I mean it includes every number. If infinity is endless and includes every number, if I roll an infinite amount of times, then, by definition, I should get every number in the universe. Since 1-6 are in the universe and on the die, all those numbers should be landed on.
Cuss this, I proved it, game over. This thread can be locked now.
Try hard.
So there is a 0 chance that you wouldn't roll a one.
Previously quoted.
There is a zero chance of that happening (meaning 1 would have to come up)
Contradiction since in one you said there is a zero chance that you would roll a one and you said there is a zero chance that you wouldn't roll a one.
well technicaly since you roll the die infidity times at some point it would need to land on one because it has a never ending amount of chances to. but then again while it is [b]very unlikly there is always a possiblity you will keep repating the same number. the possibility just becomes a decimal that is smaller and smaller after each roll.
