ForumsThe TavernMath Question

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KingLemon
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KingLemon
600 posts
Nomad

Well gosh, I feel stupid. It's been 3 months since I last did quadradic functions, oh how i hate quadradic function.
well anyways to get to the point, i seem to have forgotten how to do this simple math and was wondering if someone could help me with this question:
"Find a, b and c so that the graph of the quadratic function f(x) = ax2 + bx + c has a vertex at (-2,1) and passes through the point (0,-3)"

I need this answered ASAP, it's somewhat useless to me if someone helps solve and explain to me TOMORROW >_< so yeah please and thank you!

  • 5 Replies
Gantic
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Gantic
11,891 posts
King

Use

y = a(x - h)^2 + k

where (h , k) is the location of the vertex. Solve for a.

Nater
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Nater
1,296 posts
Nomad

Uh, english plz? MAh brainz r spinnin.

Masterforger
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Masterforger
1,824 posts
Peasant

Nater, you don't need to be here. If you can't talk maths, don't talk at all

IcyGryphon
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IcyGryphon
159 posts
Nomad

y = a(x - h)^2 + k...like already mentioned

xNightwish
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xNightwish
1,608 posts
Nomad

y = a(x - h)^2 + k

where (h , k) is the location of the vertex. Solve for a.
Look at me I'm smart.

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