ForumsThe Tavern0.999... = 1

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Talo
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Talo
945 posts
Nomad

A friend of mine brought this up, as it is a debate going on right now in the worlds of science and math. Basically, the argument is that a decimal fallowed by an infinite number of nines is actually equal to One.

The argument is simple in that:

1/3 = 0.333...
1/3 + 1/3 + 1/3 = 3/3 = 1
0.333... + 0.333... + 0.333... = 0.999...
1 = .999...

But this is all well and good for the world of Math. But science has proven a different logic, were they are not equal. My favorite example is that in science, one plus one is approximately two, due to the impurities of one. This expression basically is stating that having two halves put back together does not make it whole again.

So in my argument, I argue that if 0.999... is equal to 1, then 1 is equal to 2. I shall demonstrate using the same logic. I shall refer to an infinite amount of numbers using "..."

1 - 0.999... = 0.000...001
1 + 0.000...0001 = 1.00...001

Step 1: 0.999 = 1.000...001

0 + 0 = 0
0.000...001 + 0.000...001 = 0.000...002

Step 2: 0.000...001 + 0.000...001 = 0.000...002

2 / 1 = 2
0.000...002 / 0.000.001 = 2

Step 3: 1 = 2

  • 67 Replies
Zega
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Zega
6,921 posts
Peasant

I understand what you mean, but this is really complicated! O_O
I do not agree that 1 is 2, but i agree that 0.999999999999 is 1!

woody_7007
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woody_7007
2,662 posts
Peasant

I remember that my old maths teacher proved to us that 1=2 using algebraic quadratic equations. Buut u have never heard of this, interesting.

PixelSmash
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PixelSmash
566 posts
Nomad

Ahh, here we have the omplications of our math system... 1/3 is approximately 0.333, however it's never truely 1/3. Noting 1/3 down as one number and have it completely accurate is simply not possible!

Besides, when adding these numbers, you have to remember the significance of those numbers - 0.333... is acually 0.3333333333 as well, and the fourth number of 0.9999 needs to be rounded up, making it 1.

But yeah, tough subject

Talo
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Talo
945 posts
Nomad

basically, what I'm proving is that when you cut a cake into fractions, you have to remember there is some cake stuck to the knife. If you collect the cake from the knife after enough cuts, you can make another slice.

Talo
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Talo
945 posts
Nomad

I do not agree that 1 is 2


What part of the formula don't you agree with?
Pixie214
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Pixie214
5,838 posts
Peasant

I remembering looking at some work by a guy that had spent decades on a hugely complicated equation thats sole purpose was to prove that 1+1=2. I love that about the human mind that some can sacrifice huge parts of their lives to prove something most people take for granted fromt he age of about 5. Like PixelSmash said in most cases infinite numbers will be rounded.

woody_7007
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woody_7007
2,662 posts
Peasant

I found the algebraic way of roving 2=1

a = x [true for some a's and x's]
a+a = a+x [add a to both sides]
2a = a+x [a+a = 2a]
2a-2x = a+x-2x [subtract 2x from both sides]
2(a-x) = a+x-2x [2a-2x = 2(a-x)]
2(a-x) = a-x [x-2x = -x]
2 = 1 [divide both sides by a-x]


from this site

It gives a grasphical explanation too for those interested.
Talo
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Talo
945 posts
Nomad

You can't do that Woody. a - x = 0 so your dividing by 0. Of course the answer will come out wrong.

Zophia
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Zophia
9,434 posts
Scribe

Ow, math... But yes, once you look at the details the questions pops up...

But it is because of approximates. Two thirds will be rounded up to 0.6666...6667 unless you choose to write an infinite number. Then adding the next third with the same amount of decimals will make it one...

I agree on your thinking, though.

Talo
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Talo
945 posts
Nomad

The problem is obvious. We have no Decimal value that is exactly equal to a fraction.

woody_7007
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woody_7007
2,662 posts
Peasant

Here is a different equation that proves 1=2. It uses substitution intead.

consider
x = y -> start with this assertion

x*x = x* y -> now multiply both sides by x

x^2 = xy -> x^2 is x squared

x^2 - y^2 = xy - y^2 -> subtract y^2 from both sides

(x - y)(x + y) = y(x - y) -> factor both sides

notice that (x - y) occurs on both sides so we
can cancel or divide both sides by (x - y)

thus we have

x + y = y -> after cancelling the (x - y)

but our original assertion we have x = y
thus substituting we have

y + y = y
or
2y = 1y

cancel the y on both sides

2 = 1

Q.E.D.


Heres the site

Talo
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Talo
945 posts
Nomad

x - y = 0

You're still dividing by Zero.

Zophia
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Zophia
9,434 posts
Scribe

The problem is obvious. We have no Decimal value that is exactly equal to a fraction.
And we'll always have that problem. Is it worse or better in the binary?
Talo
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Talo
945 posts
Nomad

It's the same in binary. If we were to change the numbering system to fix this one problem, then other problems would come from it. Basically, decimals are not useful past the 3rd significant number anyways.

Also just to let you know, Tangent is the reason you can't divide by zero. There are four answers to divide by 0:

Pos Infinity
Neg Infinity
Zero
Null

IQAndreas
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IQAndreas
299 posts
Peasant

2 = 1 [divide both sides by a-x]

Actually, the reason this does not work is because you are dividing by zero, because a-x = 0

However, 0.9999999... does equal one. There is some strange name for numbers like that.

I need to check out your version of 1 = 2, though. I'm always fascinated by the way things work out in math.

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