The beginning equation 1+1=1+1 Now equating RHS (right hand side of equation) 1+1 is the RHS =1+sqrt(1) =1+sqrt[(-1)(-1)]. I hope u kno BODMAS =1+sqrt(-1) * sqrt(-1) =1+ a * a remember my assumption =1+ (-1) =1-1 = 0 Remember I was only equation the RHS ??? Well now I am going to re-insert the now equated RHS into the original formula 1+1= RHS 1+1= 0.
F.A.QuestioN
Q- there is no such thing as sqrt(-1) A- yes that is true but it is also true that when u multipy the sqrt of a number with itself you get the number of who's sqrt was taken [ Sqrt(2) * sqrt(2) = 2 ] that rule is applied here...
NO way man 1+1=1 If you have 1 pile of sand on the beach and 1 pile of sand on the beach and you put them together you have 1 pile of sand on the beach so 1+1=1 on the beach. WHAT THEN?
yes that is true but it is also true that when u multipy the sqrt of a number with itself you get the number of who's sqrt was taken [ Sqrt(2) * sqrt(2) = 2 ] that rule is applied here...
Unfortunately for you, the equation 1+1 has no multiplying the square root in it. So, 1+1=2. If the problem WAS that then it would be 0, but the problem is simply 1+1, so there's no square root. Fail argument.
