Welcome back to one of my old games, Roll A Dozen! Due to some personal reasons, i was unable to keep the original Ra12 game alive. Thus, I have created a new thread to continue the game!
Once again, here are the objectives:
Objective:
- Players must reach exactly 12 to win.
How to Play:
- A six-sided die is used.
- The player must roll the die. If an even number is used (e.g, 2, 4, 6),
you add that number to the previous rolled number.
- If an odd number is rolled (1, 3, 5) you subtract that amount from the
previous number.
- A new count always begins with the number 1.
- The player who restarts the count must roll the dice and add/subtract the
resulting number from 1.
- The count must be restarted if:
- The count reaches zero or goes into negative numbers.
- A player rolls the same number as the previous poster.
5 That's a lot of number crunching... first we need to know the probability of rolling a specific number (1/6 x 1/6 x 1/6 for a 6, 1, and another 6), then probably their order also comes into play since you can't roll a 6-6-1 or a 1-6-6, and the total number of winning combinations seems endless (we can probably reach more than 50 rolls if we don't restart when it goes over 12)... But then that's probably the surface since I'm no maths wiz
3. I completely made it up. 1d6=3
Restart.
If you count up the number of times we've won and divided it by the number of posts, that would give you an experimental probability of winning per post.
3. ANNOUNCEMENT:
I counted up all the times that we have won, and the number of posts, and deduced that the current experimental probability of a win on each post is: 1/42
Not too bad. 1d6=2
3+2=5
