ForumsForum GamesRoll A Dozen: Revived

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apldeap123
offline
apldeap123
1,708 posts
Farmer

Welcome back to one of my old games, Roll A Dozen! Due to some personal reasons, i was unable to keep the original Ra12 game alive. Thus, I have created a new thread to continue the game!

Once again, here are the objectives:

Objective:

- Players must reach exactly 12 to win.

How to Play:

- A six-sided die is used.
- The player must roll the die. If an even number is used (e.g, 2, 4, 6),
you add that number to the previous rolled number.
- If an odd number is rolled (1, 3, 5) you subtract that amount from the
previous number.
- A new count always begins with the number 1.
- The player who restarts the count must roll the dice and add/subtract the
resulting number from 1.
- The count must be restarted if:
- The count reaches zero or goes into negative numbers.
- A player rolls the same number as the previous poster.

Example:
P1: 1 (dice rolled 4) 1+4=5
P2: 5 (dice rolled 2) 5+2=7
P1: 7 (dice rolled 3) 7-3=4
P3: 4 (dice rolled 3) restart

Things to Remember:

- You can back-to-back post! Just don't post three times in a row.

Once a successful count has been reached, please notify me in my profile comments.

Now, let's begin!

  • 688 Replies
PLGuy
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PLGuy
4,755 posts
King

1. @Majestic_Fish It's on my checklist of things that "I wanna do before I die"!
Faith = 2
1+2=3

DICE RESULTS
2 = Faith
Majestic_Fish
offline
Majestic_Fish
1,917 posts
Chancellor

3. So you have faith that you will win.
Cheering = 3
Look at this 0.
RESET.

DICE RESULTS
3 = Cheering
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

1. Cheering does nothing, I'll just sit here and let the RNG have it's own uninterrupted free will.
1d6=1
The RNG hates me.

RESET

DICE RESULTS
1 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

7. I suppose we will, that's a good roll to start on.
1d6=3
7-3=4

DICE RESULTS
3 = 1d6
Yellowcat
offline
Yellowcat
2,869 posts
Treasurer

4. What if we did multiply and divide instead of add and subtract?
1d6=2
4+2=6

DICE RESULTS
2 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

6. If we did multiply and divide, we would have to standardize the rounding procedure because of fractions.
1d6=3
6-3=3

DICE RESULTS
3 = 1d6
Yellowcat
offline
Yellowcat
2,869 posts
Treasurer

7. That's true...
1d6=4
7+4=11

DICE RESULTS
4 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

11. It would be exciting, but not as exciting because it's much more difficult to standardize rules and such.
1d6=5

11-5=6

DICE RESULTS
5 = 1d6
Coral42
offline
Coral42
265 posts
Blacksmith

6. doing this inorder to do it.

DoingIT = 6

6+6 = 12

YAY!!!

DICE RESULTS
6 = DoingIT
PLGuy
offline
PLGuy
4,755 posts
King

1. Wow I thought that's impossible! Good job and great luck! I'll just start another game.

1d6=4

1+4=5

DICE RESULTS
4 = 1d6
Coral42
offline
Coral42
265 posts
Blacksmith

5. do you get anything for it? (i wiish)

1d6=2

5+2=7

DICE RESULTS
2 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

7. It would be amazing if you could get something for it. However, as was noted before, the creator hasn't been on here for 4 months.

1d6=6

7+6=13 Somebody roll a 1.

DICE RESULTS
6 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

10. Well, let's see how this goes.
1d6=6

10+6=16 Not exactly the goal, but that's better than an odd number...

DICE RESULTS
6 = 1d6
Yellowcat
offline
Yellowcat
2,869 posts
Treasurer

16. I was going to say that 16 is more helpful than 10, but it's not.
1d6=1
16-1=15

DICE RESULTS
1 = 1d6
LordLazyLeopard
offline
LordLazyLeopard
783 posts
Constable

15. That's very true, from sixteen you cannot get to twelve in one roll, whereas with fifteen you can.
1d6=1
15-1=14
You can't get to twelve in one roll from fourteen either. :/

DICE RESULTS
1 = 1d6
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