Forums → Forum Games → Roll A Dozen: Revived

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apldeap123

1,708 posts

Farmer

Posted March 2, '17 12:31pm UTC

Welcome back to one of my old games, Roll A Dozen! Due to some personal reasons, i was unable to keep the original Ra12 game alive. Thus, I have created a new thread to continue the game!

Once again, here are the objectives:

Objective:

- Players must reach exactly 12 to win.

How to Play:

- A six-sided die is used.
- The player must roll the die. If an even number is used (e.g, 2, 4, 6),
you add that number to the previous rolled number.
- If an odd number is rolled (1, 3, 5) you subtract that amount from the
previous number.
- A new count always begins with the number 1.
- The player who restarts the count must roll the dice and add/subtract the
resulting number from 1.
- The count must be restarted if:
- The count reaches zero or goes into negative numbers.
- A player rolls the same number as the previous poster.

Example:
P1: 1 (dice rolled 4) 1+4=5
P2: 5 (dice rolled 2) 5+2=7
P1: 7 (dice rolled 3) 7-3=4
P3: 4 (dice rolled 3) restart

Things to Remember:

- You can back-to-back post! Just don't post three times in a row.

Once a successful count has been reached, please notify me in my profile comments.

Now, let's begin!

Welcome back to one of my old games, Roll A Dozen! Due to some personal reasons, i was unable to keep the original Ra12 game alive. Thus, I have created a new thread to continue the game!

Once again, here are the objectives:

[b]Objective:[/b]

- Players must reach exactly 12 to win.

[b]How to Play:[/b]

- A six-sided die is used.
- The player must roll the die. If an even number is used (e.g, 2, 4, 6),
you add that number to the previous rolled number.
- If an odd number is rolled (1, 3, 5) you subtract that amount from the 
previous number.
- A new count always begins with the number 1.
- The player who restarts the count must roll the dice and add/subtract the
resulting number from 1.
- The count must be restarted if:
- The count reaches zero or goes into negative numbers.
- A player rolls the same number as the previous poster.

Example: 
P1: 1 (dice rolled 4) 1+4=5
P2: 5 (dice rolled 2) 5+2=7
P1: 7 (dice rolled 3) 7-3=4
P3: 4 (dice rolled 3) restart

[b]Things to Remember:[/b]

- You can back-to-back post! Just don't post three times in a row.

Once a successful count has been reached, please notify me in my profile comments.

Now, let's begin!

688 Replies

offline

LordLazyLeopard

783 posts

Constable

Posted October 13, '17 12:00am UTC Edited October 13, '17 12:00am UTC by LordLazyLeopard

4. I only figured it out because I randomly got the quest for playing a game on the birthday.
1d6=6
4+6=10

DICE RESULTS

6 = 1d6

offline

Yellowcat

2,869 posts

Treasurer

Posted October 13, '17 2:27am UTC Edited October 13, '17 2:27am UTC by Yellowcat

10. I think it's the same quest that's existed for the past few years, so I already have. At least I hope so, since I didn't get any quest today. Happy Birthday AG!
1d6=1
10-1=9

DICE RESULTS

1 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 13, '17 3:05am UTC Edited October 13, '17 3:05am UTC by LordLazyLeopard

9. It wouldn't surprise me if you already have it.
1d6=6
9+6=15

DICE RESULTS

6 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 14, '17 12:41am UTC Edited October 14, '17 12:41am UTC by LordLazyLeopard

1. Oh well, you can just stick around until next year if need be.
1d6=3
1-3=Restart

DICE RESULTS

3 = 1d6

offline

Yellowcat

2,869 posts

Treasurer

Posted October 14, '17 1:41am UTC Edited October 14, '17 1:42am UTC by Yellowcat

1. Next year is a bit of a long time...
1d6=3
Double Restart!
1-3=Restart
Same roll as previous=Restart

DICE RESULTS

3 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 14, '17 3:11am UTC Edited October 14, '17 3:11am UTC by LordLazyLeopard

1. Yeah, I know, it's still a possibility nonetheless.
1d6=4
1+4=5

DICE RESULTS

4 = 1d6

offline

Yellowcat

2,869 posts

Treasurer

Posted October 14, '17 2:38pm UTC Edited October 14, '17 2:38pm UTC by Yellowcat

5. I mean, I hope we all stick around till next year nevertheless.
1d6=5
Restart

DICE RESULTS

5 = 1d6

offline

sciller45

2,873 posts

Chancellor

Posted October 14, '17 3:08pm UTC Edited October 14, '17 3:09pm UTC by sciller45

1.
1d6=4=4
1 + 4 = 5

DICE RESULTS

4 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 14, '17 8:00pm UTC Edited October 14, '17 8:00pm UTC by LordLazyLeopard

5. I can't guarantee I'll be around next year because I'm going off to college and that might change things... Nonetheless, I hope so too.
1d6=2
5+2=7

DICE RESULTS

2 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 15, '17 12:07am UTC Edited October 15, '17 12:07am UTC by LordLazyLeopard

2. I doubt that they will change for me either, to be honest, but that's not my point.
1d6=2
2+2=4

DICE RESULTS

2 = 1d6

offline

sciller45

2,873 posts

Chancellor

Posted October 15, '17 9:22am UTC Edited October 15, '17 9:22am UTC by sciller45

2.
1d6=6
2+6=8

DICE RESULTS

6 = 1d6

offline

Yellowcat

2,869 posts

Treasurer

Posted October 15, '17 1:20pm UTC Edited October 15, '17 1:20pm UTC by Yellowcat

Uhhm, Correction:
4+6=10

10. I really should spend less time on AG now than I used to... but I don't.
1d6=3
10-3=7

DICE RESULTS

3 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 16, '17 5:52am UTC Edited October 16, '17 5:52am UTC by LordLazyLeopard

6. I'm aware that you knew that it wasn't my point. I, I just felt it necessary to wrap up the comment with that statement.
1d6=6
6+6=WIN! Yay!

DICE RESULTS

6 = 1d6

offline

Yellowcat

2,869 posts

Treasurer

Posted October 17, '17 9:20pm UTC Edited October 17, '17 9:20pm UTC by Yellowcat

7. No, it does not. I believe we've decided that before.
1d6=4
7+4=11

DICE RESULTS

4 = 1d6

offline

LordLazyLeopard

783 posts

Constable

Posted October 17, '17 9:45pm UTC Edited October 17, '17 9:46pm UTC by LordLazyLeopard

11. Yeah, I think that's what we decided upon.
1d6=4
11+4=15

DICE RESULTS

4 = 1d6

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